5x^2+200x-1500=0

Solution for 5x^2+200x-1500=0 equation:

5x^2+200x-1500=0

a = 5; b = 200; c = -1500;
Δ = b2-4ac
Δ = 2002-4·5·(-1500)
Δ = 70000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{70000}=\sqrt{10000*7}=\sqrt{10000}*\sqrt{7}=100\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-100\sqrt{7}}{2*5}=\frac{-200-100\sqrt{7}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+100\sqrt{7}}{2*5}=\frac{-200+100\sqrt{7}}{10}
$